Solution:
We first obtain the Thevenin equivalent.
and
Note that this is not a desirable Q-point location since VBB is very close to VBE. Variation in VBE therefore significantly change IC.We find Rac = RC || Rload= 500 W and Rdc = RC + RE =1.1KW. The value of VCE representing the quiescent value associated with ICQ is found as follows,
Then
Since the Q-point is on the lower half of the ac load line, the maximum possible symmetrical output voltage swing is
The ac power output can be calculated as
The power drawn from the dc source is given by
The power loss in the transistor is given by
The Q-point in this example is not in the middle of the load line so that output swing is not as great as possible. However, if the input signal is small and maximum output is not required, a small ICcan be used to reduce the power dissipated in the circuit.
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