To find the tensions in various parts of hanging rope loaded at various points and to compare the calculated and experimental results

To find the tensions in various parts of hanging rope loaded at various points and to compare the calculated and experimental results.

Apparatus

 A hanging rope fitted with spring balances and weights

Tension

Reaction force that produce in strings/ Elements as a action of force.

Procedure

First note the zero readings of the spring balances in the various parts of the rope A, B, C,D and E. then apply the load W₁, W_2, W₃ respectively at the B, C and D. against a vertical draw the vertical through by means of a plumb line and find the Ѳ₁ between this vertical and AB. Similarly find the Ѳ₂ between the ED and the vertical at E. now on convenient scale take a line FGHI, to represent the total load W₁ + W₂ + W₃ such that FG represents W₁ HG represents W₂ and HI represents W_3. Draw IJ and FG so that the angle <IFG = Ѳ₁ and the <FIJ = Ѳ₂ join GJ and HJ.

Satisfy yourself that FIG is the triangle of the forces for the whole rope ABCDE, also the FGJ is the triangle of forces acting at B and GHJ is the triangle of forces acting at C. hence the tensions in the parts AB, BC, CD, DE are given respectively by the magnitude of FJ,GJ,HJ,IJ. Compare these with the spring balances readings and noted the result in the table

Observations and calculations

Loads (Kg)			Forces in AB (N)		Forces in BC (N)		Forces in CD (N)		Forces in DE (N)
W1	W2	W3	By EXP	By Diag.	By EXP	By Diag.	By EXP	By Diag.	By EXP	By Diag.

Diagram: Example

          Conversion:

ΔABE= B       AE=AB=S1 =12.8 cm ΔBCE= C        BE =BC=S2=12 cm ΔCDE= C       CE=CD= S3=12.3 cm                         DE=DE= S4=13.2 cm

             Suppose: - 1cm = 3Pound